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**|**Hum Hered**|**PMC2956011

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- Abstract
- Introduction
- Methods
- Simulations
- Application to SNPs in the IL10 Gene
- Discussion
- Supplementary Material
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Hum Hered. 2010 January; 69(2): 91–103.

Published online 2009 December 4. doi: 10.1159/000264447

PMCID: PMC2956011

Thomas J. Hoffmann,^{a,}^{*} Christoph Lange,^{a,}^{b} Stijn Vansteelandt,^{c} Benjamin A. Raby,^{b} Dawn L. DeMeo,^{b} Edwin K. Silverman,^{b} Scott T. Weiss,^{b} and Nan M. Laird^{a}

*Thomas J. Hoffmann, Department of Biostatistics, 655 Huntington Ave., Bldg. 2, Fl. 4, Boston, MA 02115 (USA), Tel. +1 617 432 4927, Fax +1 617 432 5619, E-Mail moc.liamg@mffohjt

Received 2009 March 10; Accepted 2009 July 17.

Copyright © 2009 by S. Karger AG, Basel

We introduce a stepwise approach for family-based designs for selecting a set of markers in a gene that are independently associated with the disease. The approach is based on testing the effect of a set of markers conditional on another set of markers. Several likelihood-based approaches have been proposed for special cases, but no model-free based tests have been proposed. We propose two types of tests in a family-based framework that are applicable to arbitrary family structures and completely robust to population stratification. We propose methods for ascertained dichotomous traits and unascertained quantitative traits. We first propose a completely model-free extension of the FBAT main genetic effect test. Then, for power issues, we introduce two model-based tests, one for dichotomous traits and one for continuous traits. Lastly, we utilize these tests to analyze a continuous lung function phenotype as a proxy for asthma in the Childhood Asthma Management Program. The methods are implemented in the free R package fbati.

An important methodological issue in association studies of complex disorders is differentiating between true predisposing etiological allele variants and those that are only in linkage disequilibrium (LD) to those loci [Koeleman et al., 2000; Cordell and Clayton, 2002]. Our objective here is to provide methods for selecting a subset of markers in a gene which explain the disease marker association seen in the entire set. There is a complicated relationship between LD and association as described in detail in Nielsen et al. [2008]; strong LD between markers does not always guarantee redundant association results. However, testing each marker at a time, when there is even one DSL in the region, is likely to result in multiple significant χ^{2} test statistics due to the LD between the markers. In our example, multiple SNPs in the IL10 gene test as significant for association with lung function. A test is needed that can evaluate the contribution of a marker while allowing for an effect at one or more nearby markers.

Case-control methods are used in genetic studies because they can have higher power than family-based tests, but family-based tests of a main genetic effect can have the advantage of being constructed to be completely robust to population substructure and model-free [Laird and Lange, 2006]. In family-based designs, testing a genetic effect at one marker, while conditioning on another marker, has been partially considered in the literature. Koeleman et al. [2000] propose a likelihood-based approach to test for one marker in the presence of another. In a more general framework, Cordell and Clayton [2002], Cordell [2004], and Cordell et al. [2004] suggest a model-building approach using the retrospective likelihood of the genotype conditional on the trait and parental haplotype distribution to model multiple loci. This model based approach is completely robust to population substructure, but is limited to dichotomous traits and families with both parents genotyped. Dudbridge [2008] extends this model-based likelihood approach to missing parents and to quantitative traits using a normal model, but the results can be biased if the normal model does not hold. In principle, the normal model can be extended to using ascertained traits, unlike the approach we will present for quantitative traits. The approach by Dudbridge [2008] is not completely robust to population stratification when there are missing parents, but in practice it performs well when this assumption is violated. We present here methods that are applicable to arbitrary family structures, are completely robust to population stratification, and do not require distributional assumptions on the traits.

When using a test based on multiple genetic markers, we need to consider the difficulty in reconstructing the parental genotypes. When parents are effectively present, as is required in the test by Cordell and Clayton [2002], Cordell [2004], and Cordell et al. [2004] or available through nuisance parameters as in the test by Dudbridge [2008], the haplotype density and phase resolution is not very difficult to compute, even for larger numbers of markers. However, once there are missing parents, reconstructing the haplotype density and phase resolution is more difficult, and can be computationally infeasible if there are more than a few markers. Thus it is advantageous whenever possible to avoid reconstructing the haplotype density of all of the markers when parents are missing and testing multiple markers. Our approaches are constructed with this thought in mind.

We first propose a model-free test for any trait that is completely robust to population substructure and phenotypic model misspecification, and allows for arbitrary pedigrees. We then propose separate model-based tests for dichotomous and continuous traits based on a linear model. The advantage of the model-based method for dichotomous traits over the previous methodology is its method of handling missing parents. This advantage is also shared by the method for quantitative traits, which has the additional advantage of being less restrictive on the phenotypic model than previous approaches. The model-based tests are still completely robust to population substructure, but not to phenotypic model misspecification. We assess the robustness of the model-based tests to phenotypic model misspecification via simulation. In our tests, we avoid reconstructing the full haplotype density by instead conditioning on the haplotype density of small subsets of the markers, or, preferably, the univariate densities of each of the markers. This results in more informative families, especially when parents are missing. We utilize the proposed test to analyze a lung function phenotype in the Childhood Asthma Management Program (CAMP) study.

We propose several methods, all of which are completely robust to population stratification. We first propose a model-free test for any trait, and then propose separate tests for dichotomous and continuous traits that assume a log-linear and linear disease model, respectively. The latter tests are more powerful, but not completely robust to phenotypic model misspecification. Suppose that *Y*_{ij} indicates an individual's trait. Suppose the genotypes of the *k*-th marker for the *j*-th individual in the *i*-th family are given by *g*_{ij,k}, and *X*_{ij,k} = *X*(*g*_{ij,k}) is some coding of the marker, e.g. additive or genotype. We are interested in testing the set of *M* markers **X**_{ij,m} = (*X*_{ij,m1} … *X*_{ij,mm}) conditional on the set of *C* markers **X**_{ij,c} = (*X*_{ij,c1} … *X*_{ij,cC}). Suppose that the sufficient statistic for parental mating type at marker *a* is given by *S*_{a}. Let *S*_{{a,b}} = {*S*_{a}, *S*_{b}}, i.e. the sufficient statistic for parental mating type at marker *a* and the sufficient statistic for parental mating type at marker *b*, and let *S*_{H({a,b})} be the sufficient statistic for the haplotype density of the parental mating type of those markers. The distribution of the sufficient statistics for the SNP and haplotype density is given in Rabinowitz and Laird [2000] and Horvath et al. [2004]. All tests proposed are completely robust to population substructure by conditioning on the sufficient statistic for parental mating type, although some will use the haplotype density, and some will use just the SNP density.

A model-free test can be constructed similar to that of the FBAT main genetic effect statistic [Rabinowitz and Laird, 2000; Schaid, 1996]. However, instead of basing the test statistic on *P*(**X**_{ij,mk}*S*_{i,mk}), we additionally condition on the other markers using the distribution

$$P({\text{X}}_{ij,mk}|{\text{X}}_{ij,c},{S}_{i,H(mk,c)}).$$

(1)

Conditioning on *Y*_{i} is not necessary since under the null hypothesis, the distribution does not depend on *Y*, as shown in the Appendix. Let *T*_{ij} be the mean centered ${Y}_{ij}-\overline{Y}$ for quantitative traits or an indicator of disease status for dichotomous traits [Lunetta et al., 2000]. Let

$${U}_{i,mk}=\sum _{j}{T}_{ij}\left\{{\text{X}}_{ij,mk}-E\left[{\text{X}}_{ij,mk}|{S}_{i,H(mk,c)},{\text{g}}_{ij,c}\right]\right\}.$$

(2)

This is essentially the standard FBAT main genetic effect test [Laird et al., 2000; Rabinowitz and Laird, 2000] in the univariate case, except we have replaced *E*[*X**S*] by *E*[*X*_{ij,m}*S*_{i,H(mk,c)}, g_{ij,c}].

The distribution of *P*(**X**_{ij,mk}, **X**_{ij,c}*S*_{i,H(mk,c)}) is given by Horvath et al. [2004], but we do not need to estimate weights for the phases of the offspring in the cases where phase is not completely resolved. It is a very technical detail as we shall explain. We condition on the sufficient statistic for parental mating type and phase resolution to make the test robust to population substructure. It is easiest to think of the sufficient statistic as a partition of the sample space, or a set of possible outcomes consistent with what was observed or can be reconstructed about the parental mating type [Rabinowitz and Laird, 2000; Horvath et al. 2004]. Construction of this set in Horvath et al. [2004] involves finding the set of unphased genotypes that are consistent with all possible phased parental mating types. Horvath et al. [2004] then estimate the phases of the offspring; however, this is not necessary here as the disease model does not depend on phase. A similar but less general conditioning argument is given in Cordell and Clayton [2002].

Let *U*_{i,m} = (*U*_{i,m1} … *U*_{i,mM}). Then the resulting test statistic Σ_{j}*U*_{i,m} is similar to the FBAT main genetic effects test in the univariate case, or the multimarker test [Rakovski et al., 2007; Chapman et al., 2003] when multiple markers are being analyzed. However, here we have a more restrictive conditioning set for computing the expected value of **X**_{ij,mk}. Proof that this has expectation zero under the null hypothesis is provided in the Appendix. The resulting test, using the empirical variance, is given by

$${\left[\sum _{i}{U}_{i,m}\right]}^{T}{\left[\sum _{i}\left({U}_{i,m}\right){\left({U}_{i,m}\right)}^{T}\right]}^{-}\left[\sum _{i}{U}_{i,m}\right]$$

which asymptotically follows a χ^{2} distribution with rank (Σ_{i} (*U*_{i,m}) (*U*_{i,m})^{T}) degrees of freedom. We will refer to this test as the FBAT-C Robust test.

Despite the attractiveness of the completely robust test, the FBAT-C Robust test is a lot less powerful than a test based on a disease model. Thus we introduce two model-based methods. We will explore how robust the tests are to phenotypic model misspecification by simulation.

For a dichotomous trait, we can alternatively base the likelihood on the joint distribution of the markers being analyzed and conditioned on

$$P({\text{X}}_{i,\text{m}},{\text{X}}_{i,\text{c}}|{\text{Y}}_{i,}{\xi}_{i};\beta ),$$

(3)

where ξ_{i} = *S*_{i,{H({m1,c}), …,H({mM,c}),H(c)}}, rather than equation 1. By not conditioning on **X**_{i,c}, the resulting likelihood provides a more powerful test than the model-free approach, but one must assume a model for the trait, as we allow **Y**_{i} to possibly depend on **X**_{i,c}.

For a binary trait, suppose that the probability of disease is given by the generalized linear model

$$\begin{array}{ll}log(p({Y}_{ij}=1|{\text{X}}_{ij,\text{m}},{\text{X}}_{ij,\text{c}},{\xi}_{i};\beta ))\hfill & ={\alpha}_{i}+{\beta}_{\text{m}}^{T}{\text{X}}_{ij,\text{m}}+{\beta}_{\text{c}}^{T}{\text{X}}_{ij,\text{c}}\hfill \\ \hfill & ={\alpha}_{i}+{\beta}^{T}{X}_{ij}.\hfill \end{array}$$

(4)

Notice that the disease model does not depend upon phase. The intercept α_{i} allows for other individual or family effects. Covariates are not necessary to model, as we will see that they cancel out of the retrospective likelihood proposed below. Our null hypothesis is that β_{m} = 0, i.e. none of the markers in m are in linkage disequilibrium with any disease locus after adjusting for the markers in c. Suppose we additionally assume that we have phenotypic independence of the sibs, so that

$$P\left({\text{Y}}_{i}=1|{\text{X}}_{i},{\xi}_{i};\beta \right)=\prod P\left({Y}_{ij}=1|{\text{X}}_{ij},{\xi}_{i};\beta \right).$$

(5)

Such an assumption is fairly reasonable in this case since all family-specific covariates and any family factors that might be modeled in equation 4 will cancel out of the likelihood in equation 3, along with α_{i}. Using this likelihood, equations 4 and 5, and using the distribution for *P*(**X**_{i}*S*_{i,H({mk,c})}) as described in the model-free test, we can construct a score test of *H*_{0}: β_{m} = 0. The log link function in equation 4 is necessary for the baseline disease prevalence to cancel out of the formula. This also requires that we only use the affected offspring, i.e. unaffected sibs are used only to reconstruct parental haplotype transmissions. This restriction was not necessary in the model-free test, although being able to use the unaffected siblings will generally not allow to overcome the power gained from assuming a disease model. The first difference between this retrospective likelihood and the one given by Cordell and Clayton [2002] is that this likelihood conditions on the sufficient statistic for parental mating type, and so can be used when there are missing parents. Unlike the extension proposed by Dudbridge [2008], we do not estimate nuisance parameters for the parental genotypes, and so the test is completely robust to population stratification. We also use the likelihood in equation 3 instead of the product of the marginals Π_{j}*P*(**X**_{ij}*S*_{i,H({m,c})}, *Y*_{ij} = 1; β) as done by Cordell and Clayton [2002] and Dudbridge [2008], although when parents are observed under the assumption in equation 5 they are equivalent. Both Cordell and Clayton [2002] and Dudbridge [2008] also use the haplotype density of all of the markers *S*_{H({m,c})}, whereas we will use a less restrictive set.

To help us define our estimating equations, let

$$\begin{array}{l}{U}_{i,{m}_{k}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)=\sum _{j}{X}_{ij,{m}_{k}}-E\left(\sum _{j}{X}_{ij,{m}_{k}}|{\text{Y}}_{i}=1,{S}_{H(\{{m}_{k},\text{c}\})};{\beta}_{\text{m}},{\beta}_{\text{c}}\right)\hfill \\ {U}_{i,{c}_{k}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)=\sum _{j}{X}_{ij,{c}_{k}}-E\left(\sum _{j}{X}_{ij,{c}_{k}}|{\text{Y}}_{i}=1,{S}_{H(\text{c})};{\beta}_{\text{c}}\right)\hfill \\ {U}_{i,\text{m}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)={\left({U}_{i,{m}_{1}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)\dots {U}_{i,{m}_{M}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)\right)}^{T}\hfill \\ {U}_{i,\text{c}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)={\left({U}_{i,{c}_{1}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)\dots {U}_{i,{c}_{C}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)\right)}^{T}\hfill \end{array}$$

(6)

The derivatives of the log-likelihood based on equation 3 gives us the estimating equations Σ_{i}*U*_{i,m}(β_{m}, β_{c}) and Σ_{i}*U*_{i,c}(β_{m}, β_{c}). Details and proof that these have expectation zero under the null hypothesis are provided in the Appendix. We estimate the nuisance parameter β_{c} by solving the estimating equation Σ_{i}*U*_{i,c}(**0**, β_{c}) = 0. The contribution of the *i*-th family, adjusted for estimation of the nuisance parameter, is given by

$${W}_{i}={U}_{i,\text{m}}\left(0,{\stackrel{\u2038}{\beta}}_{\text{c}}\right)-\stackrel{\u2038}{E}\left[\frac{\partial}{\partial {\beta}_{\text{c}}}{U}_{i,\text{m}}\left(0,{\stackrel{\u2038}{\beta}}_{\text{c}}\right)\right]\stackrel{\u2038}{E}{\left[\frac{\partial}{\partial {\beta}_{\text{c}}}{U}_{i,\text{c}}\left(0,{\stackrel{\u2038}{\beta}}_{\text{c}}\right)\right]}^{-}{U}_{i,\text{c}}\left(0,{\stackrel{\u2038}{\beta}}_{\text{c}}\right).$$

(7)

Then the test statistic is given by (Σ_{i}*W*_{i})^{T} (Σ_{i}*W*_{i}*W*^{T}_{i})^{–} (Σ_{i}*W*_{i}). Under weak regularity conditions, this follows a χ^{2} distribution with degrees of freedom given by rank (Σ_{i}*W*_{i}*W*^{T}_{i})^{–}. We will denote this test by FBAT-C Log-Linear.

If we had instead based the likelihood on *P*(**X**_{i,mk}**X**_{i,c}, **Y**_{i} = **1**, *S*_{i,H({mk,c})}; β), the resulting score test is identical to the model-free FBAT-C Robust test. This is because then the likelihood at β_{m} = 0 no longer depends on **Y**_{i} = 1 or on β. The added power in the FBAT-C Log-Linear test comes from modeling **X**_{ij,c} rather than conditioning on it.

In practice, we would code each of the markers **X**_{ij,ck} using indicator variables for each genotype to prevent model misspecification, i.e. *X*_{ij,ck} = (*I*_{gij,ck = AA}*I*_{gij,ck = Aa}). In contrast, the coding of **X**_{ij,mk} does not affect the validity of the test. However, using either the additive coding (i.e. the number of disease alleles) or indicator variables for genotype for **X**_{ij,mk} is necessary when we are testing multiple markers conditional on another marker. With the additive coding and indicator variable coding in the bi-allelic case, the value of the test statistic does not depend on which allele is coded as the disease allele. This is not the case for a dominant or recessive coding. Using indicator variables would be most appropriate in the case of a dominant or recessive gene.

We take a slightly different approach for quantitative traits, assuming a model only for the mean of the trait. Assume that the mean of the trait follows a linear model

$$E({Y}_{ij}|{X}_{ij,\text{m}},{X}_{ij,\text{c}},{S}_{i,\left\{\text{m,c}\right\}})={\mu}_{ij}({S}_{i,\left\{\text{m,c}\right\}})+{\beta}_{\text{m}}^{T}{X}_{ij,\text{m}}+{\beta}_{\text{c}}^{T}{X}_{ij,\text{c}}.$$

(8)

We additionally assume only that Mendel's laws hold and make no distributional assumptions on the error, rather than normal error as in Dudbridge [2008]. The term μ_{ij} = μ_{ij}(*S*_{i,{m,c}}) encodes the dependence of the trait on the parental mating type. We leave this term unspecified, so that the test is completely robust to population stratification.

Let Δ*X*_{ij,mk} = *X*_{ij,mk} – *E*(*X*_{ij,mk}*S*_{i,mk}), and Δ**X**_{ij,m} = (Δ*X*_{ij,m1} … Δ*X*_{ij,mM}). The parameters β_{m} and β_{c} could be estimated using G-Estimation [Robins et al., 1992] as in Vansteelandt et al. [2008]. However, here we are instead interested in testing β_{m}, treating β_{c} as a nuisance parameter; that is, here we are coding each allele instead of grouping them as a single haplotype. Since we also assume no haplotype effect, we use a slightly different parental mating type conditioning set than Vansteelandt et al. [2008], and a very similar G-Estimator. Define the residual phenotype

$${e}_{ij}({\beta}_{\text{m}},{\beta}_{\text{c}})={Y}_{ij}-{\mu}_{ij}-{\beta}_{\text{m}}^{T}{X}_{ij,\text{m}}-{\beta}_{\text{c}}^{T}{X}_{ij,\text{c}}.$$

To define the estimating equations, similar to before, we let

$$\begin{array}{l}{U}_{i,{m}_{k}}=\sum _{j}\u25b3{X}_{ij,{m}_{k}}{e}_{ij}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)\hfill \\ {U}_{i,{c}_{k}}=\sum _{j}\u25b3{X}_{ij,{c}_{k}}{e}_{ij}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right),\hfill \end{array}$$

(9)

with *U*_{i,m} and *U*_{i,c} defined as before in equation 6. Then our estimating equations can be given by Σ_{i}*U*_{i,m} and Σ_{i}*U*_{i,c}. Note that these equations do not depend on the haplotype density at all, and so will have more informative families than the other proposed methods. The estimating equation has expectation 0 (see Appendix) for every choice of μ_{ij}. Thus the choice of μ_{ij} will not affect the validity of the test, only the power. A powerful two-step approach for estimating μ_{ij} is as follows. In the first step, we estimate μ_{ij} by the sample mean of the trait, possibly after adjustment for covariates. We then estimate β_{c} using the data. In the second step, we let μ_{ij} be the predicted value of the residual *e*_{ij}(β_{m}, β_{c}) from each strata of parental mating type. Misspecification of this second step will not invalidate the approach, but may at worst lead to some loss in power.

Construction of the test statistic then proceeds as in that of the FBAT-C Log-Linear test. The nuisance parameter is solved as before under the null hypothesis from the equation Σ_{i,j}*U*_{ij,c}(**0**, β_{c}) = 0, which has the following closed form estimate

$${\stackrel{\u2038}{\beta}}_{\text{c}}={\left\{\sum _{i,j}\u25b3{\text{X}}_{ij,\text{c}}{\text{X}}_{ij,\text{c}}^{T}\right\}}^{-1}\sum _{ij}\u25b3{\text{X}}_{ij,\text{c}}\left({Y}_{ij}-{\mu}_{ij}\right).$$

Intuitively, the estimating equation for the nuisance parameter β_{c} is very similar to the FBAT main genetic effects test. Let the contribution of the *i*-th family, adjusted for estimating the nuisance parameter, be given by

$$\begin{array}{ll}{W}_{i}\hfill & ={U}_{i,\text{m}}\left(0,{\stackrel{\u2038}{\beta}}_{\text{c}}\right)-\stackrel{\u2038}{E}\left[\frac{\partial}{\partial {\beta}_{\text{c}}}{U}_{i,\text{m}}\left(0,{\stackrel{\u2038}{\beta}}_{\text{c}}\right)\right]\stackrel{\u2038}{E}{\left[\frac{\partial}{\partial {\beta}_{\text{c}}}{U}_{i,\text{c}}\left(0,{\stackrel{\u2038}{\beta}}_{\text{c}}\right)\right]}^{-}{U}_{i,\text{c}}\left(0,{\stackrel{\u2038}{\beta}}_{\text{c}}\right)\hfill \\ \hfill & =\sum _{j}\Delta {\text{X}}_{ij,\text{m}}\left({Y}_{ij}-{\mu}_{ij}-{\stackrel{\u2038}{\beta}}_{\text{c}}^{T}{\text{X}}_{ij,\text{c}}\right)\hfill \\ \hfill & -\left[\sum _{i,j}\Delta {\text{X}}_{ij,\text{m}}{\text{X}}_{ij,\text{c}}\right]{\left[\sum _{i,j}\Delta {\text{X}}_{ij,\text{c}}{\text{X}}_{ij,\text{c}}\right]}^{-}\sum _{j}\Delta {\text{X}}_{ij,\text{c}}\left({Y}_{ij}-{\mu}_{ij}\right).\hfill \end{array}$$

Then the test statistic is given by (Σ_{i}*W*_{i})^{T} (Σ_{i}*W*_{i}*W*^{T}_{i})^{–} (Σ_{i}*W*_{i}). Under weak regularity conditions, this follows a χ^{2} distribution with rank (Σ_{i}*W*_{i}*W*^{T}_{i})^{–} degrees of freedom, as shown in the Appendix. This test statistic is intuitively similar to a test constructed by first regressing the effect of the marker being conditioned on the trait, and second using this residual as a new trait in the standard FBAT main genetics effect test of the marker being analyzed; however, the G-Estimation approach uses Mendel's laws and evaluates the contributions of all markers simultaneously. Additionally, if we were to avoid modeling *X*_{c} in equation 8, and use *S*_{{H(m1,c), … H(mM,c)}}, then the G-Estimation would yield the FBAT-C Robust test.

Each test described above (FBAT-C Robust, Log-Linear, and Linear) can be applied using a stepwise approach to determine a set of markers that best explain the association with the disease. The stepwise approach is intended to be used after a significant result has been found from a multimarker test [Chapman et al., 2003; Rakovski et al., 2007]. The stepwise approach begins with a univariate analysis of each marker, with the FBAT main genetic effects test by Rabinowitz and Laird [2000], choosing the most significant marker. Then the FBAT-C test can be applied by conditioning on the markers from the previous step, and testing each of the other markers. A step-down approach is then applied to ensure all of the markers are really necessary.

In all plots and tables displayed here, unless otherwise noted, we ran 10,000 simulations with an empirical type I error rate of 0.05. Each consisted of 500 families, of different structures as will be indicated. Results are displayed under an additive disease model.

We first compare the power of the model-based FBAT-C Log-Linear and FBAT-C Linear tests to the FBAT-C Robust test, and the other approaches proposed in the literature. For power, we simulate the data under the models given in equation 4 for dichotomous traits and equation 8 with standard normal error for continuous traits. Figure Figure11 and and22 show that the model-based methods can be substantially more powerful than the robust method for dichotomous and continuous traits, respectively. They also show that the test will not have much if any power if the markers being analyzed are too highly correlated (*R*^{2}, rather than *D*′) with the markers being conditioned on, depending on the sample size and magnitude of the effect size. If the markers are perfectly correlated, then they are indistinguishable. Results in this plot are shown for allele frequencies of 0.2 for both alleles, but the relative power difference between the tests does not change much as a function of allele frequency. We vary the allele frequencies in figure figure3;3; both the allele frequency of the marker being tested and that being conditioned on affect the power of the disease. In figure figure1,1, the FBAT-C Log-Linear test has the same power as the likelihood ratio test introduced by Cordell and Clayton [2002], since for trios the FBAT-C Log-Linear test is a score test of the same likelihood. The FBAT-C Linear model is more powerful than the normal model implemented in the software of Dudbridge [2008], largely because the latter is a two degree of freedom test while the former is a one degree of freedom test. Results are similar for discordant sibpairs; the nuisance parameters for parents do not increase the power of the test much, if at all (results shown in online supplementary figures 1 and 2, www.karger.com/doi/10.1159/000264447).

Power for trios with a dichotomous trait of the test of *X*_{m} conditional on *X*_{c}. *R*^{2} is between the markers *X*_{m} and *X*_{c}, where *X*_{m} is the DSL.

Power of the test of *X*_{m} conditional on *X*_{c} for a continuous trait using FBAT-C Linear for different allele frequencies. The two power curves, where *p*_{m} ≠ *p*_{c}, cannot be perfectly correlated (binary data), and are shown only as far as they can be **...**

Next, we explore the power of different family structures in figure figure4;4; results are similar to that of the usual FBAT main genetic effect test. Under a quantitative trait, we compare trios, sibships with two offspring and no parents (sibpairs), and sibships with three offspring and no parents (sibtrios). For the sibpairs and sibtrios, when parents are missing, we then consider the case when only one offspring in the sibship is phenotyped, which would be more common in a dichotomous trait. In this case trios are more powerful than sibtrios, which are more powerful than sibships. This relationship is preserved no matter what the allele frequency of the other model parameters are. However, with a quantitative trait, often more offspring are phenotyped, so we then compare to the cases when all of the offspring are phenotyped. When all offspring are phenotyped, the sibpair is about as powerful as trios, and the sibtrio is the most powerful.

Secondly, we test the robustness of the two model-based tests. The FBAT-C Robust test always preserves the type I error rate, so we focus here on the performance of the model-based tests. The results we display for all of the robustness tests are all done with an allele frequency of 0.2. Other allele frequencies were simulated, but the main parameter that inflated the type I error was the correlation between the markers. In the cases where the type I error was inflated, it was generally more inflated for more highly correlated markers, and for higher β_{c} values, unless otherwise specified. Thus most charts focus on showing a range of *R*^{2} values or just more extreme *R*^{2} values when other parameters are of interest, and reasonable β_{c} values. We begin by considering the robustness of the FBAT-C Log-Linear method. One potential misspecification is if the scale of the model is wrong, for example if the link function in equation 4 should instead be on a logistic scale, although they should be similar for a rare enough disease. To investigate the robustness of the test, we simulated data under the logistic model. In the results in online supplementary table 1, the model-based test is generally overly conservative, but preserves the nominal type I error rate. This does not generally translate into more power for the FBAT-C test than the FBAT-C Robust test under the misspecified case, except for the cases when the markers are very highly correlated, and there is low power of the test anyway (results not shown).

Next, we tested the robustness of the model-based tests for continuous traits to the disease model. We modeled the mean as in equation 8 with a uniform and χ^{2} variance distribution. Figure Figure55 shows that FBAT-C Linear performs as expected and desired, while the approach based on a normal likelihood [Dudbridge, 2008] has an inflated type I error. Second, we simulated what would happen if the mean was really specified by a log-normal distribution, to test what would happen when the linear model did not hold for the mean. We see very little departure from the nominal type I error rate in figure figure55 for the FBAT-C Linear test. Third, we tested whether phenotypic correlation amongst the siblings would bias the test. Even under strong phenotypic correlation, the test shows little if any departure from the nominal type I error rate (results not shown). Last, we found that the approach by Dudbridge [2008] did not inflate the type I error rate much, if at all, for discordant sibpairs (results shown in the supplementary material).

FBAT-C Linear validity results for trios. The plots of the χ^{2} and uniform distribution follow a linear model, but have nonnormal variance. The log-normal model follows a non-linear model.

In summary the model-based method for a dichotomous test often preserves the type I error rate, but is over-conservative when the log-linear conditional mean model is misspecified. The model-based method for continuous traits also performs well.

Lastly we test how well our overall strategy performs. We apply this for our FBAT-C Linear test and our FBAT-C Robust test. We additionally consider one other approach, where all markers are univariately tested, and those with a significant p value after Bonferroni correction are chosen; we denote this approach the Bonferroni approach. To simulate data to test the strategy, we use the haplotype frequency from the dataset (table (table1)1) in our application with 682 trios. We consider validity in this case to be when the approach finds a marker (or markers), but there is no association, i.e. no markers should be found because there is no DSL. Recall that the FBAT-C approaches all begin with a multimarker test, and so should be conservative in this case. When testing the validity of the test, the FBAT-C Linear and FBAT-C Robust have an empirical type I error rate of 0.018, and the Bonferroni approach has an empirical type I error rate of 0.032 (500 simulations, approximate SE 0.01). We then simulated three different cases to test how well the approach works if there really was a DSL, or two DSLs, in the set of typed markers. Lastly we looked at how well the approach would work if a DSL was untyped; we took the two most highly correlated SNPs from our dataset (correlation 0.93), using one as the untyped DSL, and saw how often the other correlated marker was chosen. Results for a continuous trait are shown in table table2,2, and are similar for a dichotomous trait (results not shown). With one DSL, the FBAT-C Linear and FBAT-C Robust tests perform similarly, as the initial univariate step is the same. However, when there is more than one DSL, then the FBAT-C Linear approach performs better than the FBAT-C Robust test. The Bonferroni approach generally does better for the case of picking up only non-DSL markers, but has a lot more cases where it picks up only one of the DSLs or one of the DSLs and additional markers (the ‘at least one DSL’ column), as would be expected.

We apply our test to six SNPs in the Interleukin-10 (IL10) gene and its promoter regions in the Childhood Asthma Management Program (CAMP), as previously described in Lyon et al. [2004]. The SNPs are shown in figure figure6.6. We use the continuous measurement of post-bronchodilator forced expiratory volume (FEV) as a proxy for lung function, adjusted for age, height, gender, weight, and race [CAMP, 1999]. There are 682 phenotyped offspring, with almost all having parental genotype information. The multimarker test [Rakovski et al., 2007] of these six markers has a p value of 0.0131, and the correlation matrix of the markers is shown in table table11.

We apply our FBAT-C Linear test, our FBAT-C Robust tests, and the normal model proposed by Dudbridge [2008] to the dataset. For illustrative purposes, we also dichotomize the trait by its median, and apply our FBAT-C Log-Linear and FBAT-C Robust tests. To demonstrate the test, we apply it in a stepwise fashion, as in stepwise regression as described above. We begin by choosing the most significant marker from the univariate FBAT main genetic effects test, which is the same as the univariate marker rs3024496 chosen by the normal model approach (table (table3).3). The results of the stepwise approach are shown in table table4.4. The strategy using the FBAT-C Linear approach, the most powerful of our proposed approaches, begins with rs3024496, and then also chooses rs1800872. These two markers are not very strongly correlated (*R*^{2} = 0.30, table table1).1). Results of the haplotype test Horvath et al. [2004] are given in table table5,5, showing that there may be an interaction between these two markers.

We began by presenting the FBAT-C Robust test, the test that is totally robust to model misspecification. The FBAT-C Robust test uses the haplotype density of all of the markers being tested and each marker being conditioned on, and has very few informative families, especially if there are lots of markers. We then introduced a disease model for a more powerful approach that generally behaves well under model misspecification. For ascertained dichotomous traits, we introduced the FBAT-C Log-Linear test. The FBAT-C Log-Linear test uses the same haplotype density at the FBAT-C Robust test, but gains an extra power boost from the disease model. Instead of conditioning on the other markers, they are jointly modeled. Finally we introduced the FBAT-C Linear test for quantitative traits. The FBAT-C Linear test does not require normal errors, and does not even need the haploytpe distribution, getting a further power boost. In our tests, we generally avoided reconstructing the haplotype density of all of the markers, and thus also did not include it in our disease model. The disadvantage of this approach is that one can no longer determine whether there is a haplotype effect of the markers, or if the markers are individually contributing to the risk of the disease. However, one can follow-up with a haplotype test, as we did in the application, to determine this. Additionally, the FBAT-C Log-Linear approach could be modified to test for haplotype effects by conditioning on the sufficient statistic for parental mating type of all of the markers rather than the set of pairwise sufficient statistics.

In our application of the FBAT-C approach to the CAMP dataset, we used a stepwise approach to choose the best set of markers to explain the variation in the trait. We assessed how well this approach worked via simulation using our dataset, comparing it to the standard univariate Bonferroni correction approach. The stepwise approach generally performs better at finding the true set of DSLs, at the cost of finding a set of markers that do not contain the DSL more often.

The software is available in the R [R Development Core Team, 2008] package fbati, available from http://cran.r-project.org/. It uses the package fgui for the graphical interface [Hoffmann and Laird, 2009], and the data loading routines of pbatR [Hoffmann and Lange, 2006]. It requires the free FBAT program [Laird et al., 2000] to run. The data format is as described in pbatR.

T.J.H. was funded by MH17119 and ES007142. N.M.L. and C.L. were funded by R01-MH059532. S.V. was supported in part by the IAP Research grant nr. P06/03 from the Belgian Government (Belgian Science Policy).

We thank all of the families for their invaluable participation in the Childhood Asthma Management Study (CAMP). We acknowledge the CAMP investigators and research team, supported by the National Heart, Lung and Blood Institute (NHLBI), National Institutes of Health, for the collection of the CAMP Genetic Ancillary Study data. All work on data collected from the CAMP Genetic Ancillary Study was conducted at the Channing Laboratory of the Brigham and Women's Hospital under appropriate policies and human subject's protections for these two studies. The CAMP Genetics Ancillary Study is supported by U01 HL075419, U01 HL65899, P01 HL083069, R01 HL086601 from the NHLBI.

Here we prove that under *H*_{0} equation 9 has expectation 0. For simplicity, we drop the *i*, *j* indices. We have that

$$\begin{array}{l}E[U|{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})},Y]\hfill \\ =(Y-\mu )E({\text{X}}_{m}-E[{\text{X}}_{m}|{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})}]|{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})},Y)\hfill \\ =(Y-\mu )E(E[{\text{X}}_{m}|{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})},Y]-E[{\text{X}}_{m}|{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})}])\hfill \end{array}$$

and hence it suffices to show that

$$E[{\text{X}}_{m}|Y,{S}_{H(\{m,\text{c}\})},{\text{g}}_{\text{c}}]=E[{\text{X}}_{m}|{S}_{H(\{m,\text{c}\})},{\text{g}}_{\text{c}}].$$

And hence it suffices to show that

$$P({\text{g}}_{m}|Y,{S}_{H(\{m,\text{c}\})},{\text{g}}_{\text{c}})=P({\text{g}}_{m}|{S}_{H(\{m,\text{c}\})},{\text{g}}_{\text{c}}).$$

(10)

We have that

$$\begin{array}{l}P\left({g}_{m}|{S}_{H(\{m,\text{c}\})},{\text{g}}_{\text{c}},Y\right)=\hfill \\ \frac{P\left(Y|{g}_{m},{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})}\right)P\left({g}_{m},{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})}\right)}{{\sum}_{{g}_{m}^{*}\u220a{S}_{H(\{m,\text{c}\})}}P\left(Y|{g}_{m}^{*},{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})}\right)P\left({g}_{m}^{*},{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})}\right)}.\hfill \end{array}$$

Now, the null hypothesis implies that *Y* · *g*_{m}**g**_{c}, *S*_{H({m,c})}, hence

$$\begin{array}{ll}P\left({g}_{m}|{S}_{H(\{m,\text{c}\})},{\text{g}}_{\text{c}},Y\right)\hfill & =\frac{P\left(Y|{g}_{\text{c}},{S}_{H(\{m,\text{c}\})}\right)P\left({g}_{m},{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})}\right)}{{\sum}_{{g}_{m}^{*}\u220a{S}_{H(\{m,\text{c}\})}}P\left(Y|{g}_{\text{c}}^{*},{S}_{H(\{m,\text{c}\})}\right)P\left({g}_{m}^{*},{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})}\right)}\hfill \\ \hfill & =\frac{P\left({g}_{m},{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})}\right)}{{\sum}_{{g}_{m}^{*}\u220a{S}_{H(\{m,\text{c}\})}}P\left({g}_{m}^{*},{\text{g}}_{\text{c}},{S}_{H(\{m,\text{c}\})}\right)}\hfill \\ \hfill & =P\left({g}_{m}|{s}_{H(\{m,\text{c}\})},{\text{g}}_{\text{c}}\right).\hfill \end{array}$$

This verifies equation 10, and so under *H*_{0} equation 2 has expectation 0.

The joint retrospective likelihood is given by

$$\begin{array}{ll}p\left({\text{X}}_{i}|{\xi}_{i},\text{Y}=1\right)\hfill & =\frac{P\left({\text{Y}}_{i}=1|{\text{X}}_{i},{\xi}_{i};\beta \right)P\left({\text{X}}_{i}|{\xi}_{i}\right)}{{\sum}_{\text{X}*\u220a{\xi}_{i}}P\left({\text{Y}}_{i}=1,\text{X}*|{\xi}_{i};\beta \right)P\left(\text{X}*|{\xi}_{i}\right)}\hfill \\ \hfill & =\frac{\left[{\prod}_{j}P\left({Y}_{ij}=1|{\text{X}}_{ij},{\xi}_{i};\beta \right)\right]P\left({\text{X}}_{i}|{\xi}_{i}\right)}{{\sum}_{\text{X}*\u220a{\xi}_{i}}\left[{\prod}_{j}P\left({Y}_{ij}=1|{\text{X}}_{j}^{*},{\xi}_{i};\beta \right)\right]P\left(\text{X}*|{\xi}_{i}\right)}\hfill \\ \hfill & =\frac{{e}^{{\sum}_{j{\beta}_{m}^{T}{\text{X}}_{ij},\text{m}+{\beta}_{\text{c}}^{T}{\text{X}}_{ij},\text{c}}}P\left({\text{X}}_{i}|{\xi}_{i}\right)}{{\sum}_{\text{X}*\u220a{\xi}_{i}}{e}^{{\sum}_{j{\beta}_{m}^{T}{\text{X}}_{j}^{*},\text{m}+{\beta}_{\text{c}}^{T}{\text{X}}_{j}^{*},\text{c}}}P\left(\text{X}*|{\xi}_{i}\right)}\hfill \end{array}$$

(11)

and so the log-likelihood contribution of each individual is

$${l}_{i}\propto \sum _{j}\left[{\beta}_{\text{m}}^{T}{\text{X}}_{ij,\text{m}}+{\beta}_{\text{c}}^{T}{X}_{ij,\text{c}}\right]-log\left\{\sum _{\text{X}*\u220a{\xi}_{i}}{e}^{{\sum}_{j{\beta}_{\text{m}}^{T}{\text{X}}_{j}^{*},\text{m}+{\beta}_{\text{c}}^{T}{\text{X}}_{j}^{*},\text{c}}}P\left(\text{X}*|{\xi}_{i}\right)\right\}$$

We then have that, for each individual marker, the derivative of the log-likelihood evaluated at β_{m} = 0, and with the conditioning set simplified (which we will show we can do in B.2), is given by

$$\begin{array}{l}{U}_{i,{m}_{k}}\left(0,{\beta}_{\text{c}}\right)=\sum _{j}{X}_{ij,{m}_{k}}-E\left(\sum _{j}{X}_{ij,{m}_{k}}|{\text{Y}}_{i},{S}_{i,H(\{{m}_{k},\text{c}\})},{\beta}_{c},{\beta}_{m}=0\right)\hfill \\ {U}_{i,\text{c}}\left(0,{\beta}_{\text{c}}\right)=\sum _{j}{X}_{ij,{c}_{k}}-E\left(\sum _{j}{X}_{ij,{c}_{k}}|{\text{Y}}_{i},{S}_{i,H(\text{c})},{\beta}_{c},{\beta}_{m}=0\right)\hfill \end{array}$$

where

$$\begin{array}{l}E\left(\sum _{j}{X}_{ij,{m}_{k}}|{\text{Y}}_{i},{S}_{i,\{{m}_{k},\text{c}\}},{\beta}_{c},{\beta}_{m}=0\right)=\hfill \\ \frac{{\sum}_{{\text{X}}_{m}^{*},{X}_{\text{c}}^{*}\u220a{S}_{i},\{{m}_{k},\text{c}\}}\left[{\sum}_{j{X}_{j}^{*},{m}_{k}}\right]{e}^{{\beta}_{\text{c}}^{T}{\sum}_{j{X}_{j}^{*},c}}P\left({\text{X}}_{m}^{*},{X}_{\text{c}}^{*}|{S}_{i,\{{m}_{k},\text{c}\}}\right)}{{\sum}_{{X}_{m}^{*},{X}_{\text{c}}^{*}\u220a{S}_{i},\{{m}_{k},\text{c}\}}{e}^{{\beta}_{\text{c}}^{T}{\sum}_{j{X}_{j}^{*},\text{c}}}P\left({\text{X}}_{m}^{*},{X}_{c}^{*}|{S}_{i,\{{m}_{k},\text{c}\}}\right)}\hfill \\ E\left(\sum _{j}{\text{X}}_{ij,{c}_{k}}|{\text{Y}}_{i},{S}_{i,\text{c}},{\beta}_{c},{\beta}_{m}=0\right)=\hfill \\ \frac{{\sum}_{{X}_{\text{c}}^{*}\u220a{S}_{i,\text{c}}}\left[{\sum}_{j{X}_{j}^{*},{c}_{k}}\right]{e}^{{\beta}_{\text{c}}^{T}{\sum}_{j{X}_{j}^{*},c}}P\left({\text{X}}_{\text{c}}^{*}|{S}_{i,\text{c}}\right)}{{\sum}_{{X}_{\text{c}}^{*}\u220a{S}_{i,\text{c}}}{e}^{{\beta}_{\text{c}}^{T}{\sum}_{j{X}_{j}^{*},\text{c}}}P\left({\text{X}}_{c}^{*}|{S}_{i,\text{c}}\right)}.\hfill \end{array}$$

Next, we show that we can simplify the conditioning set for the markers, that the estimating equation Σ_{i}*U*_{i} has expectation zero under the null hypothesis. We have that

$$E({U}_{i}|{\text{Y}}_{i}=1)=E[E({U}_{i}|{\text{Y}}_{i}=1,{\xi}_{i};{\beta}_{\text{c}},{\beta}_{\text{m}})].$$

For simplicity, we drop the *i* indices. First we show that

$$E({\text{X}}_{\text{c}}|\text{Y}=1,{S}_{H(\text{c})};{\beta}_{\text{c}};{\beta}_{\text{m}})=E({\text{X}}_{\text{c}}|\text{Y}=1,\xi ;{\beta}_{\text{c}},{\beta}_{\text{m}}).$$

It is sufficient to show that

$$P({\text{X}}_{\text{c}}|{S}_{H(\text{c})};{\beta}_{\text{c}};{\beta}_{\text{m}})=P({\text{X}}_{\text{c}}|,\xi ;{\beta}_{\text{c}},{\beta}_{\text{m}}).$$

Suppose parental genotypes are known, and phase is known of all of the markers. Then this is true by Mendel's laws. If phase is not known, but parents are still present, then we integrate over the phases of the parents and the offspring. We have

$$\begin{array}{ll}P\left({\text{X}}_{\text{c}}|\xi \right)\hfill & =\sum _{\text{phase}}P\left({\text{X}}_{\text{c}}|\text{phase},\xi \right)p\left(\text{phase}|\xi \right)\hfill \\ \hfill & =p\left({\text{X}}_{\text{c}}|{S}_{\text{c}}\right)\sum _{\text{phase}}P\left(\text{phase}|\xi \right)=p\left({\text{X}}_{\text{c}}|{S}_{\text{c}}\right)\hfill \end{array}$$

(12)

where the equality from the first to the second line again follows by Mendel's laws. Thus the result follows when parents are present. Finally suppose that one or both parents are missing. Then we again have equation 12. Now, each combination of the marker being analyzed and conditioned on can be thought of as a single multiallelic marker. Then the equality of *P*(**X**_{c}phase, ξ) = *P*(**X**_{c}, ξ) follows from Mendelian transmissions by the arguments in Rabinowitz and Laird [2000] using the sufficient statistic for a multiallelic marker. Similarly, we have that

$$E({X}_{mk}|\text{Y}=1,{S}_{H(mk,\text{c})};{\beta}_{\text{c}},{\beta}_{\text{m}},)=E({X}_{mk}|\text{Y}=1,\xi ;{\beta}_{\text{c}},{\beta}_{\text{m}}),$$

and so the estimating equations are unbiased.

Now, when adjusting for the nuisance parameter, we need the following additional derivatives, evaluated under β_{m} = 0. Let

$$\begin{array}{ll}{A}_{i,a,b}\hfill & =\sum _{{\text{X}}_{\text{m}}^{*},{\text{X}}_{\text{c}}^{*}\u220a{S}_{i}{,}_{\text{mc}}}{\left[\sum _{j}{X}_{j,{m}_{k}}^{*}\right]}^{a}{\left({\left[\sum _{j}{\text{X}}_{j,\text{c}}^{*}\right]}^{T}\right)}^{b}{e}^{{\beta}_{\text{c}}^{T}{\sum}_{j{\text{X}}_{j,\text{c}}^{*}}}P\left({\text{X}}_{mk}^{*},{\text{X}}_{\text{c}}^{*}|{S}_{i,\{{m}_{k},\text{c}\}}\right)\hfill \\ {B}_{i,a}\hfill & =\sum _{{\text{X}}_{c}^{*}\u220a{S}_{i,c}}{\left({\left[\sum _{j}{\text{X}}_{j,\text{c}}^{*}\right]}^{T}\right)}^{\otimes \text{a}}{e}^{{\beta}_{\text{c}}^{T}{\sum}_{j{\text{X}}_{j,\text{c}}^{*}}}\text{p}\left({\text{X}}_{\text{c}}^{*}|{S}_{i,\text{c}}\right),\hfill \end{array}$$

where we define *M*^{0} = 1, *M*^{1} = *M*, and *M*^{2} = *MM*^{T}. Then we have that

$$\begin{array}{ll}\frac{\partial {U}_{i,{m}_{k}}\left(0,{\beta}_{\text{c}}\right)}{\partial {\beta}_{\text{c}}}=\hfill & -\frac{{A}_{i,1,1}{A}_{i,0,0}-{A}_{i,1,0}{A}_{i,0,1}^{T}}{{A}_{i,0,0}^{2}}\hfill \\ \frac{\partial {U}_{i,\text{c}}\left(0,{\beta}_{\text{c}}\right)}{\partial {\beta}_{\text{c}}}=\hfill & -\frac{{B}_{i,2}{B}_{i,0}-{B}_{i,1}^{\otimes 2}}{{B}_{i,0}^{2}}\hfill \end{array}$$

From a Taylor series expansion, we have that

$$\begin{array}{ll}{U}_{i,\text{m}}\left({\beta}_{\text{m}},{\stackrel{\u2038}{\beta}}_{\text{c}}\right)\hfill & ={U}_{i,\text{m}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)+E\left[\frac{\partial}{\partial {\beta}_{\text{c}}}{U}_{i,\text{m}}\left({\beta}_{\text{m}}{,}_{\text{c}}\right)\right]\left({\stackrel{\u2038}{\beta}}_{\text{c}}-{\beta}_{\text{c}}\right)+{o}_{p}(1)\hfill \\ {U}_{i,\text{c}}\left({\beta}_{\text{m}},{\stackrel{\u2038}{\beta}}_{\text{c}}\right)\hfill & ={U}_{i,\text{m}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)+E\left[\frac{\partial}{\partial {\beta}_{\text{c}}}{U}_{i,\text{c}}\left({\beta}_{\text{m}}{,}_{\text{c}}\right)\right]\left({\stackrel{\u2038}{\beta}}_{\text{c}}-{\beta}_{\text{c}}\right)+{o}_{p}(1)\hfill \\ \hfill & =\left[\frac{\partial}{\partial {\beta}_{\text{c}}}\sum {U}_{i,\text{c}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)\right]\left({\stackrel{\u2038}{\beta}}_{\text{c}}-{\beta}_{\text{c}}\right)+{o}_{p}(1)\hfill \end{array}$$

Hence

$${U}_{i,\text{m}}\left({\beta}_{\text{m}},{\stackrel{\u2038}{\beta}}_{\text{c}}\right)={U}_{i,\text{m}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)$$

(13)

$$+E\left[\frac{\partial}{\partial {\beta}_{\text{c}}}{U}_{i,\text{m}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)\right]E{\left[\frac{\partial}{\partial {\beta}_{\text{c}}}{U}_{i,\text{c}}\left({\beta}_{\text{m}},{\beta}_{\text{c}}\right)\right]}^{-1}{U}_{i,\text{c}}\left({\beta}_{\text{m}},{\stackrel{\u2038}{\beta}}_{\text{c}}\right)+{o}_{p}(1)$$

(14)

It now follows from the central limit theorem that *W*_{i} (equation 7) follows an asymptotically multivariate normal distribution, with variance that can be consistently estimated by the right hand side of expression 13, replacing β_{c} with β*circ;*_{c}.

Here we show that equation 8 has expectation zero for any μ_{ij}, similar to section B.2. As an intermediate step, first we show that *f*(*g*_{m}*S*_{m}, *S*_{c}) = *f*(*g*_{m}*S*_{m}). Suppose we have both parents, and phase is resolvable, then the transmissions follow Mendel's laws, and the equation holds. If the parents are present, and phase is not resolvable, then we integrate over phases of the parents and offspring. We have

$$\begin{array}{c}f\left({g}_{m}|{S}_{m},{S}_{c}\right)={\int}_{\text{phase}}f\left({g}_{m}|{S}_{m},{S}_{c},\text{phase}\right)f\left(\text{phase}|{S}_{m},{S}_{c}\right)\\ ={\int}_{\text{phase}}f\left({g}_{m}|{S}_{m}\right)f\left(\text{phase}|{S}_{m},{S}_{c}\right),\end{array}$$

(15)

where *f*(*g*_{m}*S*_{m}, *S*_{c}, phase) = *f*(*g*_{m}*S*_{m}) follows from Mendel's laws. The result then follows when parents are present. Finally, suppose that one or both parents are missing. Then we again have equation 15. Now, each combination of the marker being analyzed and conditioned on can then be thought of as a single multiallelic marker. The equality *f*(*g*_{m}*S*_{m}, *S*_{c}, phase) = *f*(*g*_{m}*S*_{m}) then follows from Mendelian transmissions by the arguments in Rabinowitz and Laird [2000] using the sufficient statistic for a multiallelic marker.

With this result, showing that equation 8 has expectation zero proceeds similarly to that in Vansteelandt et al. [2008].

$$\begin{array}{c}E\left[\left(\u25b3{X}_{ij,m}\u25b3{X}_{ij,c}\right){e}_{ij}\left(\beta \right)\right]\\ =E\left[\left(\u25b3{X}_{ij,m}\u25b3{X}_{ij,c}\right)E\left\{{e}_{ij}\left(\beta \right)|{X}_{ij,m},{X}_{ij,c},{S}_{i,m}{S}_{i,c}\right\}\right]\\ =E\left[\left(\u25b3{X}_{ij,m}\u25b3{X}_{ij,c}\right){\mu}_{ij}\left({S}_{i,m},{S}_{i,c}\right)\right]\\ =E\left[\left(E\left(\u25b3{X}_{ij,m}|{S}_{i,m},{S}_{i,c}\right)E\left(\u25b3{X}_{ij,c}|{S}_{i,m},{S}_{i,c}\right)\right){\mu}_{ij}\left({S}_{i,m},{S}_{i,c}\right)\right]\\ =E\left[\left(E\left\{\u25b3{X}_{ij,m}|{S}_{i,m}\right\}E\left\{\u25b3{X}_{ij,c}|{S}_{i,c}\right\}\right){\mu}_{ij}\left({S}_{i,m},{S}_{i,c}\right)\right]=0,\end{array}$$

where we use that *E*(Δ*X*_{ij,m}*S*_{m}, *S*_{c}) = *E*(Δ*X*_{ij,m}*S*_{m}) from our results above.

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